Optimal. Leaf size=277 \[ \frac{45 \sqrt{\pi } \cos (a) \sqrt [3]{c+d x} \text{FresnelC}\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{b}}{\sqrt [3]{c+d x}}\right )}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{45 \sqrt{\pi } \sin (a) \sqrt [3]{c+d x} S\left (\frac{\sqrt{b} \sqrt{\frac{2}{\pi }}}{\sqrt [3]{c+d x}}\right )}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}-\frac{45 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}+\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}} \]
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Rubi [A] time = 0.264657, antiderivative size = 277, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 9, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {3435, 3417, 3415, 3409, 3385, 3386, 3354, 3352, 3351} \[ \frac{45 \sqrt{\pi } \cos (a) \sqrt [3]{c+d x} \text{FresnelC}\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{b}}{\sqrt [3]{c+d x}}\right )}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{45 \sqrt{\pi } \sin (a) \sqrt [3]{c+d x} S\left (\frac{\sqrt{b} \sqrt{\frac{2}{\pi }}}{\sqrt [3]{c+d x}}\right )}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}-\frac{45 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}+\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3435
Rule 3417
Rule 3415
Rule 3409
Rule 3385
Rule 3386
Rule 3354
Rule 3352
Rule 3351
Rubi steps
\begin{align*} \int \frac{\sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{(c e+d e x)^{10/3}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\sin \left (a+\frac{b}{x^{2/3}}\right )}{(e x)^{10/3}} \, dx,x,c+d x\right )}{d}\\ &=\frac{\sqrt [3]{c+d x} \operatorname{Subst}\left (\int \frac{\sin \left (a+\frac{b}{x^{2/3}}\right )}{x^{10/3}} \, dx,x,c+d x\right )}{d e^3 \sqrt [3]{e (c+d x)}}\\ &=\frac{\left (3 \sqrt [3]{c+d x}\right ) \operatorname{Subst}\left (\int \frac{\sin \left (a+\frac{b}{x^2}\right )}{x^8} \, dx,x,\sqrt [3]{c+d x}\right )}{d e^3 \sqrt [3]{e (c+d x)}}\\ &=-\frac{\left (3 \sqrt [3]{c+d x}\right ) \operatorname{Subst}\left (\int x^6 \sin \left (a+b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{d e^3 \sqrt [3]{e (c+d x)}}\\ &=\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}}-\frac{\left (15 \sqrt [3]{c+d x}\right ) \operatorname{Subst}\left (\int x^4 \cos \left (a+b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{2 b d e^3 \sqrt [3]{e (c+d x)}}\\ &=\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}+\frac{\left (45 \sqrt [3]{c+d x}\right ) \operatorname{Subst}\left (\int x^2 \sin \left (a+b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{4 b^2 d e^3 \sqrt [3]{e (c+d x)}}\\ &=-\frac{45 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}+\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}+\frac{\left (45 \sqrt [3]{c+d x}\right ) \operatorname{Subst}\left (\int \cos \left (a+b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}\\ &=-\frac{45 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}+\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}+\frac{\left (45 \sqrt [3]{c+d x} \cos (a)\right ) \operatorname{Subst}\left (\int \cos \left (b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}-\frac{\left (45 \sqrt [3]{c+d x} \sin (a)\right ) \operatorname{Subst}\left (\int \sin \left (b x^2\right ) \, dx,x,\frac{1}{\sqrt [3]{c+d x}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}\\ &=-\frac{45 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{8 b^3 d e^3 \sqrt [3]{e (c+d x)}}+\frac{3 \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{2 b d e^3 (c+d x)^{4/3} \sqrt [3]{e (c+d x)}}+\frac{45 \sqrt{\pi } \sqrt [3]{c+d x} \cos (a) C\left (\frac{\sqrt{b} \sqrt{\frac{2}{\pi }}}{\sqrt [3]{c+d x}}\right )}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{45 \sqrt{\pi } \sqrt [3]{c+d x} S\left (\frac{\sqrt{b} \sqrt{\frac{2}{\pi }}}{\sqrt [3]{c+d x}}\right ) \sin (a)}{8 \sqrt{2} b^{7/2} d e^3 \sqrt [3]{e (c+d x)}}-\frac{15 \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )}{4 b^2 d e^3 (c+d x)^{2/3} \sqrt [3]{e (c+d x)}}\\ \end{align*}
Mathematica [A] time = 1.25353, size = 192, normalized size = 0.69 \[ \frac{(e (c+d x))^{2/3} \left (-6 \sqrt{b} \left (\left (15 (c+d x)^{4/3}-4 b^2\right ) \cos \left (a+\frac{b}{(c+d x)^{2/3}}\right )+10 b (c+d x)^{2/3} \sin \left (a+\frac{b}{(c+d x)^{2/3}}\right )\right )+45 \sqrt{2 \pi } \cos (a) (c+d x)^{5/3} \text{FresnelC}\left (\frac{\sqrt{\frac{2}{\pi }} \sqrt{b}}{\sqrt [3]{c+d x}}\right )-45 \sqrt{2 \pi } \sin (a) (c+d x)^{5/3} S\left (\frac{\sqrt{b} \sqrt{\frac{2}{\pi }}}{\sqrt [3]{c+d x}}\right )\right )}{16 b^{7/2} d e^4 (c+d x)^{7/3}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.043, size = 0, normalized size = 0. \begin{align*} \int{\sin \left ( a+{b \left ( dx+c \right ) ^{-{\frac{2}{3}}}} \right ) \left ( dex+ce \right ) ^{-{\frac{10}{3}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: IndexError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (d e x + c e\right )}^{\frac{2}{3}} \sin \left (\frac{a d x + a c +{\left (d x + c\right )}^{\frac{1}{3}} b}{d x + c}\right )}{d^{4} e^{4} x^{4} + 4 \, c d^{3} e^{4} x^{3} + 6 \, c^{2} d^{2} e^{4} x^{2} + 4 \, c^{3} d e^{4} x + c^{4} e^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (a + \frac{b}{{\left (d x + c\right )}^{\frac{2}{3}}}\right )}{{\left (d e x + c e\right )}^{\frac{10}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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